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Basis of $\mathbb{R}$ over $\mathbb{Q}$ exists by Axiom of choice, but is it impossible to construct it and its cardinality?

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Is it hard or proven to be impossible to construct basis $B$ of $\mathbb{R}$ over $\mathbb{Q}$?

Small question regarding the cardinality:(If some miracle happened and CH turned out to be false, then cardinality of $B$ would have the possibility to be strictly between cardinality of natural numbers and real numbers. )I know by Countable/uncountable basis of vector space that it can't have countable basis.


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